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Old 04-21-2009, 12:59 PM
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Default Buzzer Circut Wiring?

So, I picked up some switches and buzzers the other day, looking to do a mini-project for something. Like if the switch is flipped to 'on', it sends power to a circut. This circut will switch to a permanent 'on' setting (there will be a switch somewhere else to turn if off, but don't consider that), sounding a buzzer. Like you flip the switch to on, buzzer goes of. Even if you flip the switch off, disconnect the power from that, the buzzer stays on, as it runs off a a seperate battery...

The Buzzer will run on up to 14 volts, its a 108db unit. Looking to have it LOUD, so higher voltage? Initial voltage from the trigger switch will be 12 volts. Any ideas/info/help? Thanks.
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Old 04-21-2009, 01:43 PM
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If I understand what you want you need to make a relay with a latching circuit wired in. 12 volt into the relayon a trip switch. The wire that will feed the buzzer needs a second wire hooked to it that will go through the hidden switch and loop back to the relay pickup coil. This is the latching portion of the circuit. Basically you have 12v constant to the main relay input or common. A switched 12v source feeds the pickup coil. The relays output is fed back to the pickup coil so that when the switched input is turned off the output is still feeding it and keeping it active. Your hidden switch needs to simply be put in line with the feedback/latching circuit wire. I'll explain better later if need be.
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Old 04-21-2009, 02:11 PM
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Quote:
Originally Posted by ZX9RBART View Post
If I understand what you want you need to make a relay with a latching circuit wired in. 12 volt into the relayon a trip switch. The wire that will feed the buzzer needs a second wire hooked to it that will go through the hidden switch and loop back to the relay pickup coil. This is the latching portion of the circuit. Basically you have 12v constant to the main relay input or common. A switched 12v source feeds the pickup coil. The relays output is fed back to the pickup coil so that when the switched input is turned off the output is still feeding it and keeping it active. Your hidden switch needs to simply be put in line with the feedback/latching circuit wire. I'll explain better later if need be.
Yeah, so I'm kinda lost. I'm with you, just not really with you. Get the jidst of it... Gonna research the "latching" thing, done some stuff like that for Robotics, just not in a long time... But to reiterate I want it to work like:

Flip switch on > power flows through to circut > buzzer turns on
flip switch off > buzzer stays on

But, it's powered by a complete seperate source, like battery.

EDIT:
Thanks, that helped, quite alot actually!
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Old 04-21-2009, 03:38 PM
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I built a safe for an electronics course at school like 10 years ago.... it sounds pretty similar to what you wanted....

I had a key switch sitting between the power source and buzzer.
I had an LED wired to the key switch so when power flowed it lit up.
I had a mini / micro switch on the door, closed the circuit was broken, open the buzzer went off.

Wasn't anything to it... just a very simply acid etched PCB with a few trace lines on it to build the circuit and then the parts....
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Old 04-21-2009, 04:41 PM
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Take an automotive fog light relay, it has 4 posts, we will call them ...
1 power
2 switched
3 output
4 ground
From your battery run a wire to your hidden master kill switch and then from there to terminal 1
run a wire from 1 to your trigger switch and from the trigger to 2
run a wire from 3 to 2 (this is the latch)
run the positive for the buzzer to 3 as well
run your negative for the buzzer as well as the negative from the battery to 4

I could try to draw a picture if it's still as clear as mud.
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Old 04-21-2009, 11:35 PM
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Do you keep leaving your headlights on sweed?
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